For saturated steam at 150 psig with 95% steam quality, what would be the enthalpy value represented in BTU/lb?

In thermodynamics, steam quality represents the proportion of steam in a saturated mixture of water and steam. In this case, with a steam quality of 95%, it indicates that 95% of the mixture is in the vapor phase, while 5% is in the liquid phase.

To find the enthalpy of steam at the specified conditions, you typically refer to steam tables, which provide enthalpy values for saturated steam and saturated water at various pressures. At a gauge pressure of 150 psig, which translates to about 164.7 psia (since atmospheric pressure is approximately 14.7 psi), the enthalpy values for both the saturated liquid and saturated vapor can be found.

For saturated steam (the vapor), the enthalpy at this pressure would be provided as a specific value in the steam tables, and generally, this value will be higher than for the saturated liquid because it includes the energy added to the water in phase change.

Since the quality is 95%, the overall enthalpy of the mixture can be determined using the formula:

[

h = h_f + x \cdot (h_g - h_f)

]

where:

• ( h ) is the enthalpy