If the primary side voltage is 13.8 KV and the secondary side voltage is 115 KV with a primary side current of 450 amps, what is the current on the secondary side?

To determine the current on the secondary side of a transformer, you can use the principle of conservation of power, which states that the power input to the transformer must equal the power output, assuming an ideal transformer with no losses. The power on both sides can be expressed as voltage multiplied by current.

Given:

• Primary voltage (Vp) = 13.8 kV

• Secondary voltage (Vs) = 115 kV

• Primary current (Ip) = 450 A

The formula for power on the primary side is:

[ P_p = V_p \times I_p ]

[ P_p = 13.8 \text{ kV} \times 450 \text{ A} ]

The power on the secondary side can be represented as:

[ P_s = V_s \times I_s ]

Setting these two power equations equal to each other (Pp = Ps), we have:

[ V_p \times I_p = V_s \times I_s ]

Now, plug in the known values:

[ 13.8 \text{ kV} \times 450 \text{ A} = 115 \text{ kV} \times I_s ]

To find ( I_s